Online ISSN: 2515-8260

Observational Study of Conduction Blocks After Acute Myocardial Infarction Admitted at Chalmeda Anand Rao Institute of Medical Sciences, Karimnagar.

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Yerrolla Sandeep1 , Akshay Dhananiwala2 , Spandana Jathoth3 , Sanjay H Kalbande4 , P. Narayana5

Abstract

Acute Myocardial infarction (AMI) is one of the most fatal diseases of human community. Its incidence is almost 2-3 times more in Indian ethnicity. Myocardial infarction leads to complications like mechanical and electrical abnormalities. Conduction blocks are seen in myocardial infarction, more commonly in Inferiorposterior wall infarction because of proximity of conduction system. Aim: This study is undertaken to evaluate various patterns of conduction blocks occurring in Acute myocardial infarction. It also corelates risk factors like diabetes mellitus and site of infarction. Material and methods: 100 cases of Acute myocardial infarction (AMI) admitted in semi urban hospital Chalmeda Anand Rao Institute of Medical Sciences, Karimnagar were included in this observational study. Results: Among 100 patients, 31 patients (31%) developed conduction blocks. Among the 100 patients, 6 patients (6%) developed first-degree AV block. 3 patients (3%) developed second – degree AV block. 3 patients (3%) developed third-degree AV block. 8 patients (8%) developed left anterior hemiblock (LAHB). 10 patients (10%) developed RBBB and 8 had complete RBBB and 2 had incomplete RBBB. This was the most common conduction block in the present study. 1patient (1%) developed LBBB and all had complete LBBB. Conclusion: Myocardial infarction is common in the age group of 50-69 years. 31% of patients with MI developed conduction blocks. Diabetes and hypertension as combined risk factors develop more conduction block complications. Complete heart block is seen more in diabetics and hypertensives. LV dysfunction after recovery from MI is noted in DM + HTN group. Mortality is more in patients with conduction blocks when compared to patients without conduction blocks (P = 0.0293).

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